Work done by 12 men in 4 days = 1 (full work) Work done by 1 man in 4 days = 1/12 Work done by 6 men in 4 days = 6/12 = 1/2 (i.e., half of the work) Work done by 6 men in 2 days = (1/2) × (2/4) = 1/4 Remaining work = 1 - 1/4 = 3/4 15 women complete the full work in 4 days → 1 woman’s 1-day work = 1/(15 × 4) = 1/60 Work needed in 3 days → x women × 3 × (1/60) = 3/4 x = (3/4) × (60/3) = 15 women
12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job, and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days?
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the ASF Airports Security Force preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.