An enzyme has a Kₘ of 4.7 x 10-5M. If the Vₘₐₓ of the preparation is 22m moles liter⁻¹ min⁻¹, what velocity would be observed in the presence of 2.0 x 10⁻⁴M substrate and 5.0 x 10⁻⁵M of a competitive inhibitor?

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An enzyme has a Kₘ of 4.7 x 10-5M. If the Vₘₐₓ of the preparation is 22m moles liter⁻¹ min⁻¹, what velocity would be observed in the presence of 2.0 x 10⁻⁴M substrate and 5.0 x 10⁻⁵M of a competitive inhibitor? Answer: 13.54μ moles liter⁻¹ min⁻¹

Question context

This question is part of ⚗️ Biochemical Engineering within the broader 🧬 Medical Science subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.