xᶻ = y² ⇔ 10⁰.⁴⁸ = 10²×⁰.⁷⁰ = 10¹.⁴⁰ ⇒ 0.48z = 1.40 ⇒ z = 140/48 = 35/12 = 2.9 (approx.)
Given that 10⁰.⁴⁸ = x, 10⁰.⁷⁰ = y and xᶻ = y², then the value of z is close to:
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.