Let S be the sample space and E be the event of selecting 1 girl and 2 boys. Then, n(S) = Number ways of selecting 3 students out of 25 = ²⁵C₃ = (25 x 24 x 23) (3 x 2 x 1) = 2300. n(E) = (₁c¹⁰ x ₂c¹⁵) = [10 x(15 x 14)/(2 x 1)] = 1050. P(E) = n(E)/n(S) = 1050/2300 = 21/46.
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
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This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.