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Three unbiased coins are tossed. What is the probability of getting at most two heads?

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Three unbiased coins are tossed. What is the probability of getting at most two heads? Answer: 7/8

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} Let E = event of getting at most two heads. Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}. ∴ P(E) = n(E)/n(S) = 7/8.

Question context

This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.