Let S be the sample space. Then, n(S) = ₂c⁵² = (52 x 51)/(2 x 1) = 1326. Let E = event of getting 1 spade and 1 heart. ∴ n(E) = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = (₁c¹³ x ₁c¹³) = (13 x 13) = 169. ∴ P(E) = n(E)/n(S) = 169/1326 = 13/102.
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.