What will be the output of the program in TurboC? #include<stdio.h> int fun(int **ptr); int main() { int i=10, j=20; const int ptr = &i; printf(" i = %5X", ptr); printf(" ptr = %d", ptr); ptr = &j; printf(" j = %5X", ptr); printf(" ptr = %d", *ptr); return 0; }

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What will be the output of the program in TurboC? #include<stdio.h> int fun(int **ptr); int main() { int i=10, j=20; const int *ptr = &i; printf(" i = %5X", ptr); printf(" ptr = %d", *ptr); ptr = &j; printf(" j = %5X", ptr); printf(" ptr = %d", *ptr); return 0; } Answer: i= FFE4 ptr=10 j=FFE2 ptr=20

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This question is part of 💡 C Programming within the broader 💻 Programming subject and appears in the DemoPaper-Pakistan preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.

What will be the output of the program in TurboC? #include<stdio.h> int fun(int **ptr); int main() { int i=10, j=20; const int *ptr = &i; printf(" i = %5X", ptr); printf(" ptr = %d", *ptr); ptr = &j; printf(" j = %5X", ptr); printf(" ptr = %d", *ptr); return 0; }

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What will be the output of the program in TurboC? #include<stdio.h> int fun(int **ptr); int main() { int i=10, j=20; const int ptr = &i; printf(" i = %5X", ptr); printf(" ptr = %d", ptr); ptr = &j; printf(" j = %5X", ptr); printf(" ptr = %d", *ptr); return 0; }