A plant with genotype AaBb can produce 4 types of gametes: AB, Ab, aB, and ab. This is because each gene (A/a and B/b) independently assort during gamete formation (Mendel's Law of Independent Assortment). The number of possible gametes = 2ⁿ, where n is the number of heterozygous gene pairs. Here, n = 2 → 2² = 4.
How many different types of gametes will be produced by plants having a genotype AaBb?
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