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In the equilibrium mixture, the concentration of hydrogen and iodine is 0. 04 moles per dm³, while that of hydrogen iodide is 0.08 per dm³. The Kc of the following given reaction will be equal to: H₂ (g) + I₂ (g) ⇌ 2HI (g)?

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In the equilibrium mixture, the concentration of hydrogen and iodine is 0. 04 moles per dm³, while that of hydrogen iodide is 0.08 per dm³. The Kc of the following given reaction will be equal to: H₂ (g) + I₂ (g) ⇌ 2HI (g)? Answer: 4

The equilibrium constant Kc is calculated using the expression: Kc = [Products] / [Reactants] For the reaction H₂ + I₂ ⇌ 2HI, Kc = [HI]² / ([H₂][I₂]) Substituting the given values gives Kc = 4.0

Question context

This question is part of 🔬 General Science within the broader 🌐 Current Affairs & GK subject and appears in the ETEA Educational Testing and Evaluation Agency preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.