Let the present ages of A and B be 3𝑥 and 4𝑥 respectively. Ten years ago: A’s age = 3𝑥−10 B’s age = 4𝑥−10 According to the question: Solving gives 𝑥=12, so A = 36, B = 48 ⇒ total = 84 years.
Ten years ago. A was half of B's in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the ETEA Educational Testing and Evaluation Agency preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.