The expression 9^2n-4^2n is always divisible by both 5 and 13. This is because the expression can be factored as a difference of squares, and since 2n is an even number, it is divisible by both the sum 9+4=13and the difference 9-4=5of the bases.
If n is a natural number the 9^2n - 4^2n is always divisible by?
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the PPSC Punjab Public Service Commission preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.