Original average = 30 ⇒ Total sum of 50 numbers = 50 × 30 = 1500 Sum of two discarded numbers = 35 + 40 = 75 New sum = 1500 − 75 = 1425 New number of elements = 50 − 2 = 48 New average = 1425 ÷ 48 = 29.6875 ≈ 29.69 But if the question asks "nearly", the closest option is: 29.69 (or rounded to 29.7 if options are in one decimal place)
The average of 50 numbers is 30. If two numbers 35 and 40 are discarded, then the average of the remaining numbers is nearly___________?
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the PPSC Punjab Public Service Commission preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.