"A” is two years older than “B” who is twice as old as “C”.If the total ages of A, B and c be 27, than how old is B?

Step 1: Set up the equations Let A, B, and C represent the ages of the three people. Based on the problem statement, we can write the following equations: • "A is two years older than B":𝐴=𝐵+2 • "B is twice as old as C": 𝐵=2𝐶, which means 𝐶=𝐵2 • "The total ages of A, B and C be 27": 𝐴+𝐵+𝐶=27 Step 2: Solve for B To find B's age, substitute the expressions for A and C in terms of B into the total age equatio (𝐵+2)+𝐵+𝐵2=27 Combine the terms with B: 2𝐵+𝐵2+2=27 Subtract 2 from both sides of the equation: 2𝐵+𝐵2=25 To eliminate the fraction, multiply the entire equation by 2: 4𝐵+𝐵=50 5𝐵=50 Divide by 5 to find the value of B: 𝐵=10 Answer: B is 10 years old.