8, 12, 16, 20, …, 96 This is an Arithmetic Progression (A.P.) where: First term (a) = 8 Common difference (d) = 12 − 8 = 4 Last term (l) = 96 l=a+(n−1)d 96=8+(n−1)×4 96−8=4(n−1) 88=4n−4 4n=92 n=23
How many terms are there in the series 8, 12, 16, 20, ______, 96?
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This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the SPSC – Sindh Public Service Commission preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.