f′(x)=2ax+b f′′(x)=2a f′′(1)=2a=2⟹a=1 f′(1)=2a(1)+b=2(1)+b=2+b=1⟹b=−1 f(x)=x2−x+c f(1)=(1)2−1+c=0+c=c f(0)=(0)2−0+c=c f(1)−f(0)=c−c=0 0
The first and second derivatives of a quadratic Polynomial at x = 1 are 1 and 2 respectively. Then the value of f(1) – f(0) is given by?
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Question context
This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the SPSC – Sindh Public Service Commission preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.