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The integral f √2x + 1 DX will be?

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The integral f √2x + 1 DX will be? Answer: 1/3(2x + 1)^2/3 + C

∫(2x+1)1/3dx u=2x+1u = 2x + 1u=2x+1 → du=2dxdu = 2 dxdu=2dx → dx=du2dx = \frac{du}{2}dx=2/du ∫u1/3⋅2du =21 ∫u1/3du /⋅4/3u/4/3 =2/1 ⋅4/3 u4/3=8/3 u4/3 8/3 (2x+1)4/3+C ∫(2x+1)1/3dx=8/3 (2x+1)4/3+C

Question context

This question is part of 📏 Arithmetic Aptitude within the broader 🧠 Aptitude Mastery subject and appears in the SPSC – Sindh Public Service Commission preparation collection. Reviewing the answer together with nearby questions helps reinforce the underlying concept and identify how it may appear in competitive exams.