The trigonal planar structure of BF₃ with bond angles of 120° is explained by sp² hybridization. Here, one s and two p orbitals of boron mix to form three equivalent sp² hybrid orbitals, which form bonds with fluorine atoms, resulting in 120° angles instead of 90°.
If pure P orbitals were used in forming the B-F bonds in BF₃ angles 90° would be expected. The actual observed bond angle is 120°. What concept might be useful in explaining the observed angles?
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